IIT JEE Main 2017 Physics Question 7 SetA


IIT JEE Main 2017 Physics Question 7 SetA: 

The variation of acceleration due to gravity g with distance d from center of the earth is best represented by (R = Earth’s radius) :

(1) IIT JEE Main 2017 Physics Question 7 SetA option 1
(2) IIT JEE Main 2017 Physics Question 7 SetA option 2
(3) IIT JEE Main 2017 Physics Question 7 SetA option 3
(4) IIT JEE Main 2017 Physics Question 7 SetA option 4

Solution

The problem can be divided into three parts as follows:
(a) Inside earth i.e. below earth’s surface: d<R,
for which acceleration due to gravity is given by
g = Gm.d/R2

(b) On Earth’s surface: d = R,
for which acceleration due to gravity is given by
gs = Gm/R2

(c) Above earth i.e. above earth’s surface: d > R,
for which acceleration due to gravity is given by
g = Gm/d2

Hence option number 4 seems to be nearest to the given case.

Answer to IIT JEE Main 2017 Physics Question 7 SetA

Correct answer to given problem No 7 of IIT JEE Main Physics paper of 2017 SetA is option number (4).


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