IIT JEE Main 2017 Physics Question 8 SetA


IIT JEE Main 2017 Physics Question 8 SetA: 

A copper ball of mass 100 gm is at a temperature T. It is dropped in a copper calorimeter of mass 100 gm, filled with 170 gm of water at room temperature. Subsequently, the temperature of the system is found to be 75°C. T is given by :
(Given : room temperature = 30°C, specific heat of copper = 0.1 cal/gm°C):

(1) 800 °C
(2) 885 °C
(3) 1250 °C
(4) 825 °C

Solution

According to the problem:
100 × 0.1 × (t – 75) = 100 × 0.1 × 45 + 170 × 1 × 45
=> 10t – 750 = 450 + 7650
=> 10t = 1200 + 7650
=> 10t = 8850
=> t =  885°C

Answer to IIT JEE Main 2017 Physics Question 8 SetA

Correct answer to given problem No 8 of IIT JEE Main Physics paper of 2017 SetA is option number (2) that is the initial temperature of copper ball is found to be 885 °C.


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