IIT JEE Main 2017 Physics Question 9 SetA


IIT JEE Main 2017 Physics Question 9 SetA: 

IIT JEE Main 2017 Physics Question 9 SetA:- An external pressure P is applied on a cube at 0°C so that it is equally compressed from all sides. K is the bulk modulus of the material of the cube and α is its coefficient of linear expansion. Suppose we want to bring the cube to its original size by heating. The temperature should be raised by:

(1) P/(3αK)
(2) P/(αK)
(3) (3α)/(PK)
(4) 3αPK

Solution

According to the problem:
K = ΔP/(-ΔV/V)
ΔV/V = P/K
therefore, V = V0 (1 + γΔt)
ΔV/V0 = γΔt
therefore,P/K = γΔt
=> Δt = P/γK
=> Δt = P/3αK

Answer to IIT JEE Main 2017 Physics Question 9 SetA

Correct answer to given problem No 9 of IIT JEE Main Physics paper of 2017 SetA is option number (1) that temperature should be raised by Δt = P/3αK.


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