IIT JEE Main 2016 Physics Question No 12

IIT JEE Main 2016 Physics Question No 12

‘n’ moles of an ideal gas undergoes a process A->B as shown in the figure. The maximum temperature of the gas during the process will be:

IIT JEE Main 2016 Physics Question No 12

(1) 9P0V0/(2nR)
(2) 9P0V0/(nR)
(3) 9P0V0/(4nR)
(4) 3P0V0/(2nR)

Solution

The equation of the process is y = mx + c
P = -(P0/V0)V + 3P0
Now PV = nRT
therefore P = nRT/V
=> (nRT/V)=-(P0/V0)V + 3P0
=> nRT=-(P0/V0)V2 + 3P0V
=> T=-(P0/nRV0)V2 + (3P0/nR)V                  … (1)
Now for maximum T,
dT/dV = 0                                                       … (2)
here dT/dV = -(2P0/nRV0)V + (3P0/nR)       … (3)
from (2) & (3) we get,
V=(3/2)V0
putting in (1) we get
T=-(P0/nRV0)(9/4V02) + (3P0/nR)(3/2)V0
=> T=(9/2)(P0V0/nR)-(9/4)(P0V0/nR)
=> Tmax = (9/4)(P0V0/nR)

Answer

Correct answer to given problem No 12 of IIT JEE Main Physics paper of 2016 is Tmax = (9/4)(P0V0/nR) i.e. option number 3.

IIT JEE Main 2016 Physics Question No 6

IIT JEE Main 2016 Physics Question No 6

Choose the correct statement:
(1) In frequency modulation the amplitude of the high frequency carrier wave is made to vary in proportion to the amplitude of the audio single.
(2) In frequency modulation the amplitude of the high frequency carrier wave is made to vary in proportion to the frequency of the audio signal.
(3) In amplitude modulation the amplitude of the high ‘frequency carrier wave is made to very in proportion to the amplitude of the audio signal.
(4) In amplitude modulation the frequency of the high frequency carrier wave is made to vary in proportion to the amplitude of the audio signal.

Solution

By definition of Amplitude Modulation we know that statement number 3 is correct.

Answer

Correct answer to given problem No 6 of IIT JEE Main Physics paper of 2016 is option number 3 which is true.

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